James Milnor Coit
Published: 2012-02
Total Pages: 0
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Purchase of this book includes free trial access to www.million-books.com where you can read more than a million books for free. This is an OCR edition with typos. Excerpt from book: This rule can be simply expressed by the general proportion: ? M: m:: W: w, where M represents the molecular weight of the substance given, m the molecular weight of the substance asked, W the real mass of the substance given, and w the real mass of the substance asked; whence w 45. The Relations of Weight to Volume. 1. To find the volume occupied by a given weight of any gas. Rule. Divide the weight of the gas given by the weight of 1 liter; the quotient is the number of liters. 2. To find the weight of any given volume of gas. Rule. Multiply the number of liters of gas by the weight of 1 liter; the product is the weight of the given volume. Examples. 1. What volume is occupied by 6.08 grams of oxygen, the weight of 1 liter of oxygen being 1.43 grams ? 6.08 -=- 1 .43 = 4.25 liters. Ans. . 2. What is the weight of 25 liters of nitrogen gas, 1 liter weighing 1.26 grams ? 1.26 x 25 = 31.5 grams. Ans. 46. Density of Gases. The density of any gas ex presses how many times the gas is heavier than hydrogen. Knowing the density, the weight of 1 liter may readily be obtained by multiplying it by the weight of 1 liter ofhydrogen, O.OS9G grams, or 1 erith. The molecular weight of any/substance being the weight of 2 volumes of the substance in the state of gas, it is evident that its density in the state of gas may be obtained by dividing its molecular weight by 2. With few exceptions, the density of any elementary gas is expressed by the same number as its atomic weight, and that of any compound gus is expressed by the same number as half its molecular weight. Thus, oxygen, O = 10; density, 16; or 1 liter weighs 16 criths. Ammonia, NH3 = 17; density, 8.5; or 1 liter weighs 8.5 criths. 47. Relation of Gaseous Volume to Pressure. To calculate the chang..